Question: c Write 6.384 correct to 1 decimal place.


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Expanded Form of 6.384
Expanded Form of 6.384: 6.384 = (6 * 10 0 ) + (3 * 1/10 1 ) + (8 * 1/10 2 ) + (4 * 1/10 3 ) 6.384 = (6 * 1) + (3 * 1/10) + (8 * 1/100) + (4 * 1/1,000) 6.384 = 6 + 3/10 + 8/100 + 4/1,000
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Related Glossary Terms
Decimal point, expanded form, place value, scientific notation, standard form (of a number), related applications, convert from expanded form to standard form, convert from standard form to scientific notation, find the place values of the digits in a number, related solutions, expanded form of 37.24, expanded form of 939,433, expanded form of 7,476.063, expanded form of 302.06, expanded form of 390,251, expanded form of 381,684.
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What can you multiply to get 384?

These: 1 x 384, 2 x 192, 3 x 128, 4 x 96, 6 x 64, 8 x 48, 12 x 32, 16 x 24
A polynomial of degree zero is a constant term
The grouping method of factoring can still be used when only some of the terms share a common factor a true b false, the sum or difference of p and q is the of the x-term in the trinomial, a number a power of a variable or a product of the two is a monomial while a polynomial is the of monomials, add your answer:.

What three numbers multiply to give you 384?
What two numbers multiply to make 384.
As a product of its prime factors in exponents: 27*3 = 384

What two numbers multiply to give you 384 but one number is a perfect square?
Actually, there are THREE correct answers:4 x 96 = 38416 x 24 = 38464 x 6 = 384
What is the missing number in this sequence 1 2 8 48 384?
The answer is 3,840. You multiply the numbers in the sequence by 2, 4, 6, 8, then 10. 1 x 2 = 2 2 x 4 = 8 8 x 6= 48 48 x 8 = 384 384 x 10 = 3,840
What is 24 times by 16?
How many square feet are in a 16' by 24' room.
384 You just multiply the two numbers...that's squared 16x24=384
How many square foot is a room of 16x24?
Multiply the length by the width to get area. This would be 384 square feet.
How do you find the volume of a base area of 32 cm squared with a height of 12 cm?
Multiply the base area by the height, and you have the volume.
What is 384 percent as a decimal?
384 percent = 384/100 = 3.84
What is 768 divided by 2?
What is 32 times 12, what is 384 multiplied by 384, what is a percentage of 384.
the percentage of 384 = 38400%

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To write decimals in standard form, move the decimal point to the right until it is at the right of the first nonzero digit. Then, multiply the number by 10 to the power of the negative of the number of spaces the decimal point was moved.
To round to two decimal places, refer to the third decimal place. If this digit is 5 or higher, raise the second decimal place up by one; if it is 4 or lower, leave the second decimal place as is. Then, omit the third decimal place and all ...
To write a number in expanded form, break apart a number, and write it as the sum of each place value. For example, 8324 = 8000 + 300 + 20 + 4. Decimals may also be expanded in a similar format: 0.239 = 0.2 + 0.03 + 0.009.
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Write 6.384 correct to 1 decimal place ? Get the answers you need, now!
VIDEO ANSWER: In this problem, we have been given a decimal number as six point 384, and we have to write this right up to Only one decimal
To eliminate the last digit in 6.384, we use the following Two Decimal Places Rules to get the answer: Two Decimal Places Rule #1: If the last digit in 6.384 is
1. /. 1. Next. » loading. Related Glossary Terms. Decimal Point · Expanded Form
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5.8 rounded to “one decimal place”,. 6 rounded to “one significant figure”. “Decimal places” are to the right of the “decimal point.”.
Write each of the following numbers correct to the number of decimal places stated: (a), 0.3741 to 2 d.p.. 0.37. (b), 3.8451 to 2 d.p.. 3.85. (c), 142.8315 to 1
Write each of the following numbers correct to the number of decimal places stated: (a) 0.3741 to. 2 d.p.. (b) 3.8451 to. 2 d.p.. (c) 142.8315 to. 1 d.p.. (d)
What is half of 256? How is a micro gram expressed in decimal places? 2.14 expressed as a fraction? What is 2913 divided by 6 with remainder?
In computing, decimal32 is a decimal floating-point computer numbering format that occupies 4 bytes (32 bits) in computer memory.